Student: sakshi Tiwari

Q. (4/6)6×(2/3)2×(3/2)x=1 find the value of x


Answer :

Hi Sakshi,  Here is the solution.

Topic : Simplification and Algebra

Method :

Question is (4/6)6×(2/3)2×(3/2)x=1 find the value of x

On solving, (4/6)6×(2/3)2×(3/2)x=1

We get,  4 * (2 / 3 ) * 3 * x = 1

On simplifying, 4 * 2  * x = 1

We get, 8x = 1

Hence  x = 1/8

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